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=200R-0.4R^2
We move all terms to the left:
-(200R-0.4R^2)=0
We get rid of parentheses
0.4R^2-200R=0
a = 0.4; b = -200; c = 0;
Δ = b2-4ac
Δ = -2002-4·0.4·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-200}{2*0.4}=\frac{0}{0.8} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+200}{2*0.4}=\frac{400}{0.8} =500 $
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